SSC CPO 2020 PYQ — Question 147

The correct answer is Option 1 i.e. $\frac{2}{9}$.

Let the original fraction be x/y

⇒ ${x\times{160\over100}}\over{y\times{140\over100}}$ = $\frac{16}{63}$

⇒ ${x\times{8\over5}}\over{y\times{7\over5}}$ = $\frac{16}{63}$

⇒ ${{8x\over5}}\over{{7y\over5}}$ = $\frac{16}{63}$

⇒ ${{8x\over5}}\times 63 = {16 \times {7y\over5}}$ 

⇒  ${{x}}\times 9 = {2 \times {y}}$ 

⇒ ${x\over y} = {2\over9}$

Hence, The original fraction is $\frac{2}{9}$.