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SSC Selection Post 2020 PYQ — Question 58

SSC Selection Post - Matriculation Level 2020 - 9 Nov 2020 - Shift 1 • Quantitative Aptitude • Q58

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If the numerator of a fraction is increased by 20% and the denominator is decreased by 30%, the fraction obtained is 392539\over25.The original fraction is:

 

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Correct answer: D

Explanation

The correct answer is option 4 i.e. 9110091\over100.

Let original fraction = x/y

1.2x0.7y=3925⇒12x7y=3925⇒xy=273300=91100\frac{1.2x}{0.7y} = \frac{39}{25} \Rightarrow \frac{12x}{7y} = \frac{39}{25} \Rightarrow \frac{x}{y} = \frac{273}{300} = {\frac{91}{100}}