If the number 34k56k is divisible by 6, then what will be the largest value of k?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 6.
Since k is a digit, the maximum possible value of (k + k) = 18
The sum of the digits of the number = (3 + 4 + k + 5 + 6 + k) = 18 + 2k
Here, 34k56k would be divisible by 6, if 2k is divisible by 6
Possible values of 2k are multiples of 6 i.e. 6,12,18
Hence, to be divisible by 2, the number must have an even number in the unit place
The maximum value of 2k would be 12 & k would be 6
6 will be the largest value of k