If the length and breadth of a cuboid are increased by 6% and 8%, respectively, then the percentage increase in its volume (correct to two decimal places) is:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 14.48%.
Let's assume the original length and breadth of the cuboid are L and B, respectively.
New length: L + 6% of L = 1.06L
New breadth: B + 8% of B = 1.08B
Original volume: V = L × B × H (where H is the height)
New volume: V' = 1.06L × 1.08B × H = 1.1448 × L × B × H
Percentage increase in volume: [(New volume - Original volume) / Original volume] × 100 = [(1.1448V - V) / V] × 100 = 14.48%
Therefore, the percentage increase in volume is 14.48%.