If the height of a cone is tripled and the radius is halved, how does the volume change?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. Becomes three-fourths of the original.
Original volume (V) = (1/3)πr2h
New radius (r’) = r/2
New height (h’) = 3h
New volume = (1/3) × π × (r/2)2 × (3h) = (1/3)πr2h × 3/4 = (3/4)V
So, the new volume of the cone becomes three-fourths of the original.