If the equation of a line is 3x − 5y = 15, what is the equation of the line perpendicular to it that passes through the point (3, 2)?
Show answer & explanation
Correct answer: B
Explanation
Equation of the line = 3x − 5y = 15, Point = (3, 2)
According to the formula:
y = mx + c, Slope of the perpendicular line = −1/m
3x − 5y = 15
⇒ y = (3/5)x − 3
m = 3/5
Perpendicular slope = −5/3
y − 2 = (−5/3)(x − 3)
y − 2 = (−5/3)x + 5
y = (−5/3)x + 7