If the difference between two numbers is 42 and their LCM and HCF are 1729 and 7, respectively what is the sum of those rwo numbers?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 224
Let's assume the two number is 7a and 7b.
ATQ,
7a - 7b = 42
a - b = 6
Their LCM = 1729
HCF = 7
We know that
ab × HCF = LCM
ab = 1729/7 = 247
ab = 247
So, the possible number = 19 × 13 = 247
So, the first number = 7 × 19 = 133
Second number = 7 × 13 = 91
Their sum = 113 + 91 = 224