SSC CGL 2019 PYQ — Question 61

SSC CGL - 6th June 2019 - Shift 1 • Quantitative Aptitude • Q61

If the 8-digit number 2074x4y2 is divisible by 88, then the value of (4x + 3y) is:

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e. 45

Concept

Understanding

Application

For divisibility by 88, number should be divisible by 11 and 8 both.

2074x4y2 is divisible by 88

For divisible by 8 last 3 digits of the number (4y2) must be divisible by 8.

So, the value of y can be 3 or 7.

For divisibility by 11, the difference of the sum of digits at the odd place and the sum of digits at even place must be zero or divisible by 11.

So, (2 + 4 + 4 + 0) - (y + x + 7 + 2) = 0 or 11

Now, x + y – 1 = 0 (for y = 3)

x + 3 – 1 = 0

x = -2 ……digit cannot be negative

And, 

x + y – 1 = 0 (for y = 7)

x = -6 ……digit cannot be negative

So, x + y – 1 = 11

x = 5 for y = 7

4x + 3y = 20 + 21 = 41 (not in options)

x = 9 for y = 3

We have x = 9 and y = 3

4x + 3y = 36 + 9 = 45