If the 6-digit number 57zxy8 is divisible by each of 7,11 and 13, then (x- 2y + z) is:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. -1.
Since 7 × 11 × 13 = 1001, a number divisible by 7, 11, and 13 must be divisible by 1001
For a 6-digit number ABCXYZ, if ABC - XYZ = 0 or ±1001, the number is divisible by 1001
Number = 57zxy8
⇒ 57z = xy8
5 = x; 7 = y; z = 8
(x - 2y + z) = 5 - 2(7) + 8 = 5 - 14 + 8 = -1