If the 6-digit number 479xyz is exactly divisible by 7, 11 and 13, then the product of the digits x, y and z will be:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 252.
7 × 11 × 13 = 1001
Number 479xyz divisible by 1001 ⇒ must be 479479
So, x = 4, y = 7, z = 9
Product = 4 × 7 × 9 = 252