SSC CHSL 2024 PYQ — Question 64

SSC CHSL - 09 July 2024 - Shift 3 • Quantitative Aptitude • Q64

If Tanya walks at the speed of 6 km/h, she misses a train by 2 minutes. However, if she walks at the speed of 8 km/h, she reaches the station 3 minutes before the arrival of the train. The distance covered by Tanya to reach the station is:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 2 km.

Let the distance to the station be 'd' kilometers.

⇒ The difference in time between the two walking speeds is 2 minutes (missing) + 3 minutes (early) = 5 minutes.

⇒ Time at 6 km/h: Time = Distance / Speed = d / 6 hours

⇒ Time at 8 km/h: Time = Distance / Speed = d / 8 hours

⇒ 5 minutes = 5/60 hours = 1/12 hours

⇒ Since Tanya takes 1/12 hour less time at 8 km/h:

⇒ (d / 6) - (d / 8) = 1/12

⇒ (24): (4d / 24) - (3d / 24) = 2/24

⇒ d / 24 = 2/24

⇒ d = 2 kilometers

Therefore, the distance covered by Tanya to reach the station is 2 kilometers.