SSC CHSL 2024 PYQ — Question 58

SSC CHSL - 11 July 2024 - Shift 4 • Quantitative Aptitude • Q58

If tanA + sinA = x, tanA - sinA = y, what is the value of x2 - y2?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e.  4xy4\sqrt{xy}.

x2 - y2 = (x + y)(x - y)

⇒ x2 - y2 = (tanA + sinA + tanA - sinA)(tanA + sinA - tanA + sinA)

⇒ x2 - y2 = (2 tanA)(2 sinA) = 4 tanA sinA   .....(1)

Also, xy = (tanA + sinA)(tanA - sinA) = tan2A - sin2A

⇒ xy = (sin2A/cos2A) - sin2A

⇒ xy cos2A = sin2A - sin2A cos2A = sin2A(1 - cos2A) = sin2A sin2A = sin4A

⇒ xy = sin4A/cos2A = tan2A sin2A

⇒ tanA sinA = √(xy)

So, x2 - y2 = 4√(xy)

Therefore, the value of x2 - y2 is 4√(xy).