If tanA + sinA = x, tanA - sinA = y, what is the value of x2 - y2?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. .
x2 - y2 = (x + y)(x - y)
⇒ x2 - y2 = (tanA + sinA + tanA - sinA)(tanA + sinA - tanA + sinA)
⇒ x2 - y2 = (2 tanA)(2 sinA) = 4 tanA sinA .....(1)
Also, xy = (tanA + sinA)(tanA - sinA) = tan2A - sin2A
⇒ xy = (sin2A/cos2A) - sin2A
⇒ xy cos2A = sin2A - sin2A cos2A = sin2A(1 - cos2A) = sin2A sin2A = sin4A
⇒ xy = sin4A/cos2A = tan2A sin2A
⇒ tanA sinA = √(xy)
So, x2 - y2 = 4√(xy)
Therefore, the value of x2 - y2 is 4√(xy).