If tanA + secA = 5 and A is acute, then find the value of tanA.
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Correct answer: D
Explanation
tanA + secA = 5
Let tanA = x
secA = 5 − x
sec²A − tan²A = 1
(5 − x)² − x² = 1
25 − 10x + x² − x² = 1
25 − 10x = 1
10x = 24
x = 12/5
tanA = 12/5