If tanA = 1/(√(10)) , A is an acute angle, then the value of sinA + cosecA is :

If tanA = 1/(√(10)) , A is an acute angle, then the value…

If tanA = $\frac{1}{\sqrt{10}}$ , A is an acute angle, then the value of sinA + cosecA is :

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. $\frac{12}{\sqrt{11}}$ .

tan(A) = 1/√10

Perpendicular = 1 and Base = √10

Hypotenuse = √(Perpendicular² + Base²) = √[1² + (√10)²] = √(1 + 10) = √11

Now, sinA + cosecA = (1/√11) + √11 = 12/√11

Therefore, the required value is 12/√11.