If tan2A - 6 tan A + 9 = 0, 0 < A < 90°, what is the value of 6 cot A + 8cosA?
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Correct answer: D
Explanation
The correct answer is option 4 i.e. 10
tan2A - 6tan A + 9 = 0
⇒ (tan A - 3)2 = 0
⇒ (tan A - 3) = 0
⇒ tan A = 3
So, P/B = 3/1
Now,
H2 = 32 + 12
⇒ H2 = 9 + 1
⇒ H2 = 10
⇒ H = (10)½
So, cos A = 1/(10)½
Now,
6 cot A + 8 (10)½ cot A = 6 × (1/3) + 8 (10)½ × (1/10)
⇒ 2 + 8
⇒ 10