If tan θ = 8/15 , then the value of √(())/(1-sinθ)1+sinθ is :

If tan θ = 8/15 , then the value of √(())/(1-sinθ)1+sinθ…

If tan $\theta$ = $\frac{8}{15}$ , then the value of $\sqrt\frac{1-sin\theta}{1+sin\theta}$ is :

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Correct answer: B

Explanation

The correct answer is Option 2 i.e. $\frac{3}{5}$ .

tan θ = 8/15 = P/B

H = √(8² + 15²) = 17

Now, $\sqrt\frac{1-sin\theta}{1+sin\theta}=\sqrt\frac{1-\frac{8}{17}}{1+\frac{8}{17}}$

$=\sqrt{\frac{\frac{9}{17}}{\frac{25}{17}}}$

= 3/5