SSC Selection Post 2025 PYQ — Question 76

SSC Selection Post - Graduation Level - 25th July 2025 - Shift 3 • Reasoning • Q76

If # = square of the number
@ = cube of the number
% = reciprocal of the number
& = square root of the number
Evaluate:
9 # + 8 @ - 4 &

Show answer & explanation

Correct answer: D

Explanation

# = Square of the number

@ = Cube of the number

& = Square root of the number

Expression:

9# + 8@ - 4&

Now substitute the values ​​of the symbols:

9# = 9² = 81

8@ = 8³ = 512

4& = √4 = 2

Hence,

81+512−2

=593−2

=591

Correct answer: 591