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SSC CHSL 2020 PYQ — Question 56

SSC CHSL - 19th October 2020 - Shift 1 • Quantitative Aptitude • Q56

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If (Sinx + Cosx)/(Sinx – Cosx) = 6/5, then find the value of (tan2x + 1)/(tan2x – 1).

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Correct answer: B

Explanation

The correct answer is Option 2 i.e 61/60.

Understanding/Application

(Sinx + Cosx)/(Sinx – Cosx) = 6/5

Applying componendo and dividendo -

(sinx + cosx + sinx - cosx)/(sinx + cosx - sinx + cosx) = (6 + 5)/(6 - 5)

sinx/cos = 11

tanx = 11

(tan2x + 1)/(tan2x - 1)

= (112 + 1)/(112 - 1)

= 122/120

= 61/60