SSC CHSL 2025 PYQ — Question 73

sin A = 5/13
According to the formula:
sin²A + cos²A = 1
tan A = sin A / cos A
cos A = √(1 − sin²A)
= √(1 − (5/13)²)
= √(1 − 25/169)
= √(144/169)
= 12/13
tan A = $\frac{\left( \frac{5}{13} \right)}{\left( \frac{12}{13} \right)} = \frac{5}{13} \times \frac{13}{12} = \frac{5}{12}$