If sinA = and 7cot B = 24, then the value of (secAcosB)(cosecB tanA) is:
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Correct answer: C
Explanation
The correct answer is option 3 i.e.
In case of sinA = = p/h
Base2 = 169 - 25 = 144
b = 12
In case of 7cot B = 24
cot B = 24/7 = b/p
hypotenuse2 = 576 + 49 = 625
h = 25
SecA = 13/12 and TanA = 5/12
CosB = 24/25 and CosecB = 25/7
(secAcosB)(cosecB tanA) = 13/12 × 24/25 × 25/7 × 5/12 = 65/42