If sin2 θ = 2sinθ - 1, 0° ≤ θ ≤ 90°, then find the value of : 
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Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 2
sin2 θ = 2sinθ - 1
sin2 θ - 2sinθ + 1 = 0
(Sin θ - 1)2 = 0
Sin θ = 1
Sin θ = Sin 90°
θ = 90°
= (1 + Cosec 90°)/(1 - Cot 90°)
= (1 + 1)/1 - 0
= 2