The correct answer is option 2 i.e. cosAcosCsin(A−C).
cosAcosBsin(A−B) + cosBcosCsin(B−C)
=cosAcosBsinAcosB−cosAsinB+cosBcosCsinBcosC−cosBsinC
=cosAcosBsinAcosB−cosAcosBcosAsinB+cosBcosCsinBcosC−cosBcosCcosBsinC
= (sin A/cos A) - (sin B/cos B) + (sin B/cos B) - (sin C/cos C)
= tan A - tan B + tan B - tan C
= tan A - tan C
= (sin A/cos A) - (sin C/sin C)
=cosAsinCcosBsinA−cosAsinB
=cosAcosCsin(A−C)