If sinθ + cosecθ = 2, then the value of sin2θ + cosec2θ is:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e 2.
| Understanding/Application |
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sinθ + cosecθ = 2 sq. both side - (sinθ + cosecθ)2 = 4 sin2θ + cosec2θ + 2 sinθ(cosecθ) = 4 sin2θ + cosec2θ + 2 sinθ (1/sinθ) = 4 |
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sin2θ + cosec2θ = 4 - 2 sin2θ + cosec2θ = 2 |