SSC CGL 2024 PYQ — Question 62

The correct answer is Option 4 i.e. $2\over17$.

sin B = ${15\over 17} = {P \over H}$

(8, 15, 17) are the Pythagorean triplets

⇒ cos B = ${B \over H}={8\over 17}$,  sec B = ${17\over 8}$,  tan B = ${P \over B}={15\over 8}$

Now, the value of cos B(sec B – tan B)

⇒ ${8\over 17} \times({17\over8} - {15\over8})$

⇒ ${8\over 17} \times({2\over8})$

⇒ $2\over17$