SSC CHSL 2025 PYQ — Question 52

sin A = 7/25
cos B = 24/25
According to the formula:
sin(A + B) = sin A cos B + cos A sin B
sin²θ + cos²θ = 1
cos A = √(1 − sin²A)
= √(1 − (7/25)²)
= √(1 − 49/625)
= √(576/625)
= 24/25
sin B = √(1 − cos²B)
= √(1 − (24/25)²)
= √(1 − 576/625)
= √(49/625)
= 7/25
$\sin A \cos B + \cos A \sin B = \left( \frac{7}{25} \times \frac{24}{25} \right) + \left( \frac{24}{25} \times \frac{7}{25} \right) \\ = \frac{168}{625} + \frac{168}{625} \\ = \frac{336}{625}$