If sin A = 4/5 and A is acute, find cot(90 ^° - A).

If sin A = $\frac{4}{5}$ and A is acute, find cot(90 $^\circ$ - A).

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. $\frac{4}{3}$ .

cot(90° − A) = tan A

Given, sin A = $4\over5$

⇒ cos A = $3\over5$

So,

tan A = $sin A\over cos A$ = ${4\over5} \over {3\over5}$ = $\frac{4}{3}$

SSC CGL 2025 PYQ — Question 55