If sin A = , find the value of (3sin A - 4cos A)2 + (4sinA + 3cos A)2.
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 25.
Let p = sin A, q = cos A
sin A = 2/3 ⇒ sin2A = 4/9
cos A = √(1 – sin2A) = √(1 – 4/9) = √(5/9) = √5/3
So sin2A + cos2A = p2 + q2 = 1
(3sin A - 4cos A)2 + (4sinA + 3cos A)2
= (3p – 4q)2 + (4p + 3q)2
= 9p2 + 16q2 – 24pq + 16p2 + 9q2 + 24pq
= 25p2 + 25q2
= 25(p2 + q2)
= 25 × 1
= 25