SSC CGL 2025 PYQ — Question 58

The correct answer is option 1 i.e. $\frac{(1+\sqrt{10})}{3}$.

sin A = $\frac{1}{\sqrt{10}}$ = $P\over H$

here, P = Perpendiculr, H = Hypotaneous, B = Base

⇒ B² = ($\sqrt10$)² - (1)²

⇒ B² = 10 - 1 = 9

⇒ B = 3

⇒ tan A = $1\over3$

⇒ sec A = $√10\over3$

So,

tan A + sec A = $1\over3$ + $√10\over3$ = $\frac{(1+\sqrt{10})}{3}$