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SSC CGL 2022 PYQ — Question 62

SSC CGL - 02 Dec 2022 - Shift 1 • Quantitative Aptitude • Q62

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If sec2A + tan2A = 4/17, then sec4A - tan4A is equal to:

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Correct answer: C

Explanation

The correct answer is option 3 i.e. 4/17.

Given:

sec2A + tan2A = 4/17

Formula used:

a2 - b2 = (a + b)(a - b)          ---- (1)

sec2A - tan2A = 1

Calculations:

sec4A - tan4A can be written as

⇒ sec4A - tan4A = (sec2A + tan2A)(sec2A - tan2A)

Hence, sec4A - tan4A = 4/17