If 0°< θ < 90°, then what is the value of (cosec θ + cos θ + cot θ)?
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Correct answer: D
Explanation
The correct answer is option 4 i.e. .
(secθ + tanθ)/(secθ - tanθ) = 5/3
⇒ 3secθ + 3tanθ = 5secθ - 5tanθ
⇒ 8tanθ = 2secθ
⇒ 4(sinθ/cosθ) = 1/cosθ
⇒ sinθ = 1/4
⇒ cosθ = √(1 - sin²θ) = √(15/16) = √15/4
⇒ tanθ = sinθ/cosθ = (1/4)/(√15/4) = 1/√15
So, cosecθ + cosθ + cotθ = 4 + √15/4 + √15 =