If sec + tan = √3, then the positive value of sin + cos is:
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Correct answer: A
Explanation
The correct answer is Option 1 i.e. .
sec + tan = √3.....(1) and,
sec - tan = 1/√3...........(2)
Adding eq 1 and 2
⇒ 2 sec = √3 + 1/√3
⇒ 2 sec = (3 + 1)/√3
⇒ 2 sec = 4/√3
⇒ sec = 2/√3
We know that,
⇒ sec = H/B = 2/√3
So,
⇒ H2 = B2 + P2
here, H = Hypotaneous, B = Base and, P = Perpendicular
⇒ P2 = 4 - 3
⇒ P = 1
⇒ sin = P/H = 1/2
and,
⇒ cos = 1/sec
⇒ cos = √3/2
Then, the value of sin + cos
⇒ 1/2 + √3/2 = (1 + √3)/2