SSC CHSL 2023 PYQ — Question 51

SSC CHSL - 08 Aug 2023 - Shift 4 • Quantitative Aptitude • Q51

If sec θ  + tan θ = 131\over \sqrt3, then the positive value of cot θ + cos θ is:

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 332{3 \sqrt3}\over 2.

If secθ - tanθ = x then

secθ + tanθ = 1/x

So,

⇒ secθ + tanθ = 131\over \sqrt3 ....(1)

⇒ secθ - tanθ = 3\sqrt3 .....(2)

From equation 1 and 2

⇒ 2secθ = 131\over \sqrt3 + 3\sqrt3

⇒ 2secθ = 434\over \sqrt3

⇒ secθ = 232\over \sqrt3

⇒ secθ = sec 30°

⇒ θ = 30°

Now,

The value of  cot θ + cos θ

⇒ cot 30° + cos 30°

⇒ 3\sqrt3 + 32\sqrt3 \over 2 = 3323\sqrt3 \over 2