If sec A + tan A = p, then what is sec A in terms of p?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e.
sec A + tan A = p
(sec A + tan A)(sec A − tan A) = 1
p × (sec A − tan A) = 1
sec A − tan A = 1 / p
Add both equations
(sec A + tan A) + (sec A − tan A) = p + 1/p
2 sec A = p + 1/p
sec A = (p + 1/p) / 2 = (p2 + 1) / (2p)