SSC CGL 2023 PYQ — Question 68

The correct answer is Option 1 i.e. $\frac{112}{81}$.

$sec\theta=\frac{4}{3} = {H\over B}$

We know that sec²θ - 1 = tan²θ = (4/3)² - 1 = 7/9

the value of tan²θ + tan⁴θ

⇒ tan²θ(1 + tan²θ) = tan²θ × sec²θ

⇒ 7/9 × 16/9 = $\frac{112}{81}$