SSC Selection Post 2020 PYQ — Question 60

The correct answer is Option 2 i.e. 5.

secθ = 13/5

Triangle sides: 5, 12, 13

tanθ = 12/5; cosecθ = 13/12; sinθ = 12/13

$\frac{10tan\theta +24cosec\theta}{39sin\theta-10sec\theta}$

= [(10 × 12/5 + 24 × 13/12)/(39 × 12/13 - 10 × 13/5)]

= [(24 + 26)/(36 - 26)]

= 50/10

= 5