If radius of a sphere is decreased by 48%, then by what percent does its surface area decrease?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 72.96%
Given that
If the radius of a sphere is decreased by 48%
then percent does its surface area decrease = successive of 48% and 48%
= 48 + 48 - (48 *48/100) = 96 - 23.04 = 72.96%