If ∆PQR ∼ ∆FED, ∠P = 52°, ∠Q = 74°, ∠R = 54°, ∠D = 54°, ∠E = 74° ∠F= 52°, then which of the following is correct?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. ∆PQR ∼ ∆FED
Given that
If ∆PQR ∼ ∆FED, ∠P = 52°, ∠Q = 74°, ∠R = 54°, ∠D = 54°, ∠E = 74° ∠F= 52°,
According to the question
In ∆PQR and ∆FED, ∠P = ∠F = 52°, ∠Q = ∠E = 74°, ∠R = ∠D = 52°
So, All angles of both triangles are the same
Hence, both triangles are similar triangles i.e. ∆PQR ∼ ∆FED