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SSC CGL 2024 PYQ — Question 51

SSC CGL - 13 Sep 2024 - Shift 1 • Quantitative Aptitude • Q51

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If p(3+cot30°)=tan360°−2sin60°{ \sqrt{3} } + cot30°) = tan^3 60° - 2sin 60°  , Then the value of p is :

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Correct answer: C

Explanation

The correct answer is option 3 i.e. 1.

P (3+cot30°)=tan360°−2sin60°{ \sqrt{3} } + cot30°) = tan^3 60° - 2sin 60°

⇒ P(3+3)=33−2×32({ \sqrt{3} } + \sqrt{3} ) =3\sqrt{3} - 2\times\frac{\sqrt{3} } {2 }

 ⇒ P(23)=33−3({ 2\sqrt{3} } ) =3\sqrt{3} - \sqrt{3}

P = 2323\frac {2\sqrt{3}}{ 2\sqrt{3}} = 1