SSC CGL 2018 PYQ — Question 2

SSC CGL Tier II Quant - 20/02/2018 • Quantitative Aptitude • Q2

If P = 22 + 62 + 102 + 142 + … 942 and Q = 12 + 52 + 92 + … 812, then what is the value of P – Q?

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 (i.e. 26075)

P = 22 + 62 + 102 + 142 + ..... 942

No. of terms =   =24

Q = 12 + 52 + 92 + ..... 812

No. of terms =  = 21

(P – Q) = (22 – 12) + (62 – 52) + ..... (822 – 812) + 862 + 902 + 942

(P – Q) = (3 + 11 + 19 ..... + 163) + 7396 + 8100 + 8836

(P – Q) = 21 × 83 + 24332

= 26075