SSC CHSL 2020 PYQ — Question 59

SSC CHSL - 20th October 2020 - Shift 1 • Quantitative Aptitude • Q59

If p + (1/p) = 112, find (p - 112)15 + (1/p15).

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e 0

⇒ p + 1 / p = 112

⇒ p - 112 = -1 / p

Raising the power to 115 in both the sides.

⇒ (p - 112)115 = (-1 / p)115

We will add 1 / p115 in both the sides.

⇒ (p - 112)115 + 1 / p115 = - 1 / p115 + 1 / p115

⇒ (p - 112)115 + 1 / p115 = 0