If one man or two women or three boys can finish a work in 121 days, then how many days will one man, one woman and one boy together take to finish the same work?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 66.
We know that,
(M1 × T1)/W1 = (M2 × T2)/W2
According to the question,
⇒ M = 2W
⇒ W = M/2
⇒ M = 3B
⇒ B = M/3
⇒ M + W + B = M + (M/2) + (M/3) = 11M/6
⇒ (1 × 121)/1 = ((11M/6) × T2)/1
⇒ T2 = 66 days
The time taken by one man, one woman, and one boy together to finish the work is 66 days.