SSC CHSL 2021 PYQ — Question 51

SSC CHSL - 5 Aug 2021 - Shift 1 • Quantitative Aptitude • Q51

If cot4θ + cos2θ = 1, and θ < 90° then find the value of cosec3θ(sin2θ - 1).

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Correct answer: A

Explanation

The correct answer is option 1 i.e.  -1

cotθ=cosθ/sinθcotθ = cosθ/sinθ

1–sin2θ=cos2θ1 – sin2θ = cos2θ

cot4θ + cos2θ = 1

⇒ cot4θ = 1 – cos2θ

⇒ cot4θ = sin2θ

⇒ cos4θ/sin4θ = sin2θ

⇒ cos4θ = sin6θ

⇒ cos2θ = sin3θ

cosec3θ(sin2θ - 1) = cosec3θ × (- cos2θ)

So, 

= cosec3θ × (-cos2θ)

⇒ cosec3θ × (-sin3θ)

⇒ -1