SSC CHSL 2023 PYQ — Question 63

SSC CHSL - 17 Aug 2023 - Shift 2 • Quantitative Aptitude • Q63

If cosecA + cotA = ab\sqrt{b}, then find the value of (a2b−1)(a2b+1)\frac{(a^2b - 1)}{(a^2b + 1)}.

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. cosA.

cosec A + cot A = a√b.

Square both sides: (cosec A + cot A)2 = (a√b)2

Expanding: cosec2 A + 2(cosec A)(cot A) + cot2 A = a2b

Use identity: cosec2 A = 1 + cot2 A

Substituting: (1 + cot2 A) + 2(cosec A)(cot A) + cot2 A = a2b

Simplifying: 1 + 2cot2 A + 2(cosec A)(cot A) = a2b

We need to find: (a2b − 1) / (a2b + 1)

Substitute a2b = 1 + 2cot2 A + 2(cosec A)(cot A) into the expression.

Simplifying the numerator and denominator:

= (2cot2 A + 2(cosec A)(cot A)) / (2cot2 A + 2(cosec A)(cot A) + 2)

Factor out 2 and cancel:

= (cot2 A + (cosec A)(cot A)) / (cot2 A + (cosec A)(cot A) + 1)

= cot A / cosec A

= cos A