If cosecA + cotA = a, then find the value of .
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. cosA.
cosec A + cot A = a√b.
Square both sides: (cosec A + cot A)2 = (a√b)2
Expanding: cosec2 A + 2(cosec A)(cot A) + cot2 A = a2b
Use identity: cosec2 A = 1 + cot2 A
Substituting: (1 + cot2 A) + 2(cosec A)(cot A) + cot2 A = a2b
Simplifying: 1 + 2cot2 A + 2(cosec A)(cot A) = a2b
We need to find: (a2b − 1) / (a2b + 1)
Substitute a2b = 1 + 2cot2 A + 2(cosec A)(cot A) into the expression.
Simplifying the numerator and denominator:
= (2cot2 A + 2(cosec A)(cot A)) / (2cot2 A + 2(cosec A)(cot A) + 2)
Factor out 2 and cancel:
= (cot2 A + (cosec A)(cot A)) / (cot2 A + (cosec A)(cot A) + 1)
= cot A / cosec A
= cos A