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SSC CPO 2022 PYQ — Question 106

SSC CPO - 10 Nov 2022 - Shift 1 • Quantitative Aptitude • Q106

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If cos48°=mn=\frac{m}{n}, then sec 48° - cot 42° is equal to:

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Correct answer: D

Explanation

 The correct answer is option 4 i.e.  n−n2−m2m\frac{n-\sqrt{n^2-m^2}}{m}

Given that

If cos48°=mn=\frac{m}{n}, then sec 48° - cot 42°

= sec 48° - tan 48°

= n/m - √(n2 - m2)/m

= n−n2−m2m\frac{n-\sqrt{n^2-m^2}}{m}