If cos(x - y) = √3/2 and sin (x + y) = 1, where x and y are positive acute angles and x ≥ y, then x and y are: (0°< (x + y) ≤ 90°)
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Correct answer: D
Explanation
The correct answer is Option 4 i.e. 60°;30°.
cos(x - y) = √3/2
x - y = 300 .....(1
sin(x + y) = 1
x + y = 900 .....(2
Adding eq.(1 and (2 -
2x = 1200
x = 600
Putting value of x in eq(2 -
60 + y = 90
y = 90 - 60 = 300