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SSC CPO 2025 PYQ — Question 141

SSC CPO - 10 Dec 2025 - Shift 1 • Quantitative Aptitude • Q141

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If cos⁡θ=m2−n2m2+n2\cos \theta = \frac{m^2 - n^2}{m^2 + n^2} , then what is tanθ ?

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Correct answer: A

Explanation

cos⁡θ=m2−n2m2+n2\cos \theta = \frac{m^2 - n^2}{m^2 + n^2}

According to the formula:

sinθ = 2mn/(m² + n²)

tanθ = sinθ / cosθ

tanθ = [2mn/(m² + n²)] ÷ [(m² − n²)/(m² + n²)]

= 2mn/(m² − n²)