SSC CHSL 2025 PYQ — Question 53

SSC CHSL - 14 Nov 2025 - Shift 2 • Quantitative Aptitude • Q53

If cos A = 5/13 and sin B = 12/13 find sin A cos B + cos A sin B:

Show answer & explanation

Correct answer: A

Explanation

Has been given :

cos A = 5/13

sin B = 12/13

According to the formula:

sin(A + B) = sin A cos B + cos A sin B

sin²θ + cos²θ = 1

sin A = √(1 − cos²A)

= √(1 − (5/13)²)

= √(1 − 25/169)

= √(144/169)

= 12/13

cos B = √(1 − sin²B)

= √(1 − (12/13)²)

= √(1 − 144/169)

= √(25/169)

= 5/13

Now

sin A cos B + cos A sin B

= (12/13 × 5/13) + (5/13 × 12/13)

= 60/169 + 60/169

= 120/169