SSC CHSL 2025 PYQ — Question 61

SSC CHSL - 30 Nov 2025 - Shift 3 • Quantitative Aptitude • Q61

If cos A = 4/5 and A is acute, then find the value of (1 + tan² A) / (1 + cot² A).

Show answer & explanation

Correct answer: C

Explanation

Given:

cos A = 4/5, where A is an acute angle.

According to the formulas:

1 + tan²A = sec²A

1 + cot²A = cosec²A

(1 + tan²A) / (1 + cot²A) = sec²A / cosec²A

sec²A / cosec²A = (1/cos²A) / (1/sin²A)

= sin²A / cos²A

= tan²A

cos A = 4/5

sin A = 3/5

tan A = sin A / cos A

= (3/5) / (4/5)

= 3/4

tan²A = (3/4)² = 9/16