SSC CPO 2023 PYQ — Question 130

The correct answer is option 2 i.e. $\sqrt{3} \over 2$.

Given that

If $cos\;A\;={{1} \over 2},\;0 \leq A \leq$90º,

cos 60º = $1 \over 2$

⇒ A = 60º

According to the question

sin (180º - 60º) = sin 120º = $\sqrt{3} \over 2$