If ax + by = 1 and bx + ay = 2ab/(a2 + b2) then (x2 + y2)(a2 + b2) is equal to:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 2
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Application |
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ax + by = 1 and bx + ay = 2ab/(a2 + b2) Put x = 0 and y = 1 From the first equation: 0 + b = 1 ⇒ b = 1 Put x = 0, y = 1 and b = 1 in 2nd equation: 0 + a = 2a/(a2 + 1) ⇒ a2 + 1 = 2 ⇒ a2 = 1 ⇒ a = 1 Now, put x = 0, y = 1, b = 1 and a = 1 in given equation: ⇒ (x2 + y2)(a2 + b2) = (0 + 1)(1 + 1) = 2 |